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A beam of light consisting of two wavelengths 6500 A  and 5200 A  is used to obtain interference fringes in Young’s double slit experiment.  The distance between the slits is 2 mm and the distance between the plane of the slits and the screen is 120 cm.  Find the distance of the 10th bright fringe from the central maximum  corresponding to shorter wavelength
 
Options:
A .  1.1 mm
B .  2.6 mm
C .  2.8 nm
D .  3.12 mm
Answer: Option D
:
D
d=2mm.D=120cm,λ=5200˙A
ybright=nλDd
y10=10×5200×10101.22×103
=52×6×105m=3.12mm
y10=10λDd

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