Question
a3 - b3 is always divisible by:
Answer: Option A
:
A
Take a=2 and b=1 and check.
Alternatively, we know the algebraic identity,
a3−b3=(a−b)(a2+2ab+b2)
Hence , we can see that (a−b) is a factor of a3 - b3
Thus,a3 - b3is divisible by (a−b)
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:
A
Take a=2 and b=1 and check.
Alternatively, we know the algebraic identity,
a3−b3=(a−b)(a2+2ab+b2)
Hence , we can see that (a−b) is a factor of a3 - b3
Thus,a3 - b3is divisible by (a−b)
Was this answer helpful ?
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