Question
A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of ∠AOP is 60∘. Find the value of x.
Answer: Option A
:
A
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A
∠AOP+∠AON=90∘ (as ON is perpendicular to POQ)
Given, ∠AOP=60∘
⟹∠AON=90∘−60∘
∠AON=30∘
By Laws of reflection,
∠AON=∠BON=x
Thus, x=30∘
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