A person observes the angle of elevation of the top of a 60m tower from a point on the level ground to be 60 ∘ . Find the distance between the person and the foot of the tower. Options: A . &nbsp 30 m B . &nbsp 20 √ 3 m C . &nbsp 20 m D . &nbsp 60 m

Answer: Option B : B In Δ A B C , tan(60 ∘ ) = B C A B ⇒ √ 3 = 60 x ⇒ x = 20 √ 3 ⇒ Distance between the person and the tower = x = 20 √ 3 m.

A person observes the angle of elevation of the top of a 60m tower from a point

Question

A person observes the angle of elevation of the top of a 60m tower from a point on the level ground to be 60 $^{\circ}$ . Find the distance between the person and the foot of the tower.

Options:

A . 30 m

B . 20

\sqrt{3}

C . 20 m

D . 60 m

Answer: Option B
:
B

In $Δ A B C$ , tan(60 $^{\circ}$ ) = $\frac{B C}{A B}$

$\Rightarrow$ $\sqrt{3} = \frac{60}{x}$

$\Rightarrow$ x = 20 $\sqrt{3}$

$\Rightarrow$ Distance between the person and the tower = x = 20 $\sqrt{3}$ m.

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