Question
A number when divided by 6 leaves a remainder 3. When the square of the same number is divided by 6, the remainder is:
Answer: Option D
- Let x = 6q + 3. Then, x2 = (6q + 3)2 = 36q2 + 36q + 9 = 6(6q2 + 6q + 1) + 3.
So, when x2 is divided by 6, remainder = 3
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- Let x = 6q + 3. Then, x2 = (6q + 3)2 = 36q2 + 36q + 9 = 6(6q2 + 6q + 1) + 3.
So, when x2 is divided by 6, remainder = 3
Was this answer helpful ?
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