A mixture contains wine and water in the ratio 3 : 2 and another mixture contain

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A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many litres of the latter must be mixed with 3 litres of the former so that the resulting mixture may contain equal quantities of wine and water = ?

Options:

A . $$5\frac{2}{5}{\text{ litres}}$$

B . $$5\frac{2}{3}{\text{ litres}}$$

C . $$4\frac{1}{2}{\text{ litres}}$$

D . $$3\frac{3}{4}{\text{ litres}}$$

Answer: Option A

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