Question
A man performs $$\frac{2}{15}$$ of the total journey by rail, $$\frac{9}{20}$$ by bus and the remaining 10 km, on the cycle. His total journey is :
Answer: Option D
Let the distance covered by man be x km
Journey covered by rail = $$\frac{2x}{15}$$
Journey covered by bus = $$\frac{9x}{20}$$
Remaining covered by cycle = 10 km
$$\eqalign{
& \therefore x\left( {1 - \frac{2}{{15}} - \frac{9}{{20}}} \right) = 10 \cr
& \Rightarrow x\left( {\frac{{60 - 8 - 27}}{{60}}} \right) = 10 \cr
& \Rightarrow x\left( {\frac{{25}}{{60}}} \right) = 10 \cr
& \Rightarrow x = \frac{{10 \times 60}}{{25}} \cr
& \Rightarrow x = 24{\text{ km}} \cr} $$
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Let the distance covered by man be x km
Journey covered by rail = $$\frac{2x}{15}$$
Journey covered by bus = $$\frac{9x}{20}$$
Remaining covered by cycle = 10 km
$$\eqalign{
& \therefore x\left( {1 - \frac{2}{{15}} - \frac{9}{{20}}} \right) = 10 \cr
& \Rightarrow x\left( {\frac{{60 - 8 - 27}}{{60}}} \right) = 10 \cr
& \Rightarrow x\left( {\frac{{25}}{{60}}} \right) = 10 \cr
& \Rightarrow x = \frac{{10 \times 60}}{{25}} \cr
& \Rightarrow x = 24{\text{ km}} \cr} $$
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