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Question
A horizontally-launched projectile arcs out and hits the ground below
Options:
A .  d→x=v→x⋅t\overrightarrow{d}_x=\overrightarrow{v}_x\cdot tdx​=vx​⋅t
B .  d→y=+12⋅g⋅t2+v→yi⋅t\overrightarrow{d}_y=+\frac{1}{2}\cdot g\cdot t^2+\overrightarrow{v}_{yi}\cdot tdy​=+21​⋅g⋅t2+vyi​⋅t
C .  v→yf=v→yi+g⋅t\overrightarrow{v}_{yf}=\overrightarrow{v}_{yi}+g\cdot tvyf​=vyi​+g⋅t
D .  t=2⋅d→ygt=\sqrt{\frac{2\cdot\overrightarrow{d}_y}{g}}t=g2⋅dy​​​
Answer: Option D

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