Question
A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per m2 . Find the total cost of carpeting the hall.
Answer: Option A
:
A
Area of parallelogram = Base × corresponding height
Area of parallelogram = 8 × (1.75 × 8)
Area of parallelogram= 112m2 .
Total cost of carpeting the hall = Cost per m2×Area
= ₹ 2/m2 × 112 m2 = ₹ 224.
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:
A
Area of parallelogram = Base × corresponding height
Area of parallelogram = 8 × (1.75 × 8)
Area of parallelogram= 112m2 .
Total cost of carpeting the hall = Cost per m2×Area
= ₹ 2/m2 × 112 m2 = ₹ 224.
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