Lakshya Education MCQs

Question: $$\eqalign{
& {\text{If}} \cr
& {\text{I = }}\frac{3}{4} \div \frac{5}{6}{\text{,}} \cr
& {\text{II = 3}} \div \left[ {\left( {4 \div 5} \right) \div 6} \right]{\text{,}} \cr
& {\text{III = }}\left[ {{\text{3}} \div \left( {4 \div 5} \right)} \right] \div {\text{6,}} \cr
& {\text{IV = 3}} \div {\text{4}} \div \left( {5 \div 6} \right), \cr
& {\text{Then - }} \cr} $$
Options:
A.I and II are equal
B.I and III are equal
C.I and IV are equal
D.All are equal
Answer: Option C

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More Questions on This Topic :

Question 1. The least number that must be subtracted from 63522 to make the result a perfect square is = ?
  1.    18
  2.    20
  3.    24
  4.    30
Answer: Option A
Question 2. The simplification of $$\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}\, = ?$$
  1.    5
  2.    $$\frac{5}{3}$$
  3.    $$\frac{5}{{12}}$$
  4.    $$\frac{3}{4}$$
Answer: Option C
Question 3. Simplify : $$\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?$$
  1.    $$\frac{{100}}{{101}}$$
  2.    $$\frac{{90}}{{101}}$$
  3.    $$\frac{{20}}{{101}}$$
  4.    $$\frac{{101}}{{100}}$$
Answer: Option C
Question 4. The difference of $${\text{1}}\frac{3}{{16}}$$  and its reciprocal is equal to = ?
  1.    $$1\frac{1}{8}$$
  2.    $$\frac{4}{3}$$
  3.    $$\frac{{15}}{{16}}$$
  4.    None of these
Answer: Option D
Question 5. Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?
  1.    a
  2.    b
  3.    c
  4.    All equal
Answer: Option C
Question 6. If $$\sqrt {{\text{4096}}} $$  = 64, then the value of $$\sqrt {{\text{40}}{\text{.96}}} $$   $$ + $$ $$\sqrt {{\text{0}}{\text{.4096}}} $$   $$ + $$ $$\sqrt {{\text{0}}{\text{.004096}}} $$    $$ + $$ $$\sqrt {{\text{0}}{\text{.00004096}}} $$     up to two place of decimals is = ?
  1.    7.09
  2.    7.10
  3.    7.11
  4.    7.12
Answer: Option C

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