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Question
7 log (1615)+5 log(2524)+3 log(8180) is equal to -
Options:
A .  0
B .  1
C .  log 2
D .  log 3
Answer: Option C
:
C
7log(1615)+5log(2524)+3log(8180)
alogx=logxa
log(1615)7+log(2524)5+log(8180)3
logx+logy=log(x×y)
log(167157.255245.813803)
=log2

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