Question
If A, B, C are the angles of a triangle such that C is an obtuse angle, then
Answer: Option A
:
A
Since C is obtuse therefore A and B both are acute and A + B is also acute.
Hence tanA,tanB and tan(A+B) are all + ive
tan(A+B)=tanA+tanB1−tanAtanB=+ive
Above is possible only when tanAtanB<1
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:
A
Since C is obtuse therefore A and B both are acute and A + B is also acute.
Hence tanA,tanB and tan(A+B) are all + ive
tan(A+B)=tanA+tanB1−tanAtanB=+ive
Above is possible only when tanAtanB<1
Was this answer helpful ?
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