Question
54 is divided into two parts such that sum of 10 times the first part and 22 times the second part is 780. What is the bigger part?
Answer: Option A
:
A
Let the 2 parts of 54 be x and y
x+y = 54 ....(i)
and 10x + 22y = 780 ...(ii)
Multiply (i) by 10 , we get
10 x + 10 y = 540 ...(iii)
Subtracting (ii) from (iii)
- 12y = - 240
y = 20
Subsituting y = 20 in x + y = 54 ,
⟹ x + 20 = 54
⟹x = 34
Hence, x = 34 and y = 20
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:
A
Let the 2 parts of 54 be x and y
x+y = 54 ....(i)
and 10x + 22y = 780 ...(ii)
Multiply (i) by 10 , we get
10 x + 10 y = 540 ...(iii)
Subtracting (ii) from (iii)
- 12y = - 240
y = 20
Subsituting y = 20 in x + y = 54 ,
⟹ x + 20 = 54
⟹x = 34
Hence, x = 34 and y = 20
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