Question
28 is divided into two parts in such a way that 65 of one part is equal to 23 of the other. What would be the smaller part?
Answer: Option C
:
C
Let one part be x.
Then, other part = 28−x
Given that
65 of one part = 23 of the other
⇒65x=23(28−x)
⇒(6×32)x=5(28−x)
⇒9x=5(28−x)
⇒9x=140−5x
⇒14x=140
⇒x=10
The other part would be 28 - 10 = 18
Hence, thesmallerpart is 10.
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:
C
Let one part be x.
Then, other part = 28−x
Given that
65 of one part = 23 of the other
⇒65x=23(28−x)
⇒(6×32)x=5(28−x)
⇒9x=5(28−x)
⇒9x=140−5x
⇒14x=140
⇒x=10
The other part would be 28 - 10 = 18
Hence, thesmallerpart is 10.
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