2. The solution of the differential equation 2 d2Yk --2- = y - y2 under th

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2. The solution of the differential equation 2 d2Yk --2- = y - y2 under the boundary dx conditions (i) y = yi at x = 0 and (ii) y = y2 at x = 00, where k, y1 and y2 are constants, is

Options:

A . y = (y1 - y2) exp(-x/k2) + y2

B . y = (y2 - y1) exp(-x/k) + yi

C . y = (y1 - y2) sin h(x/k) + y1

D . y = (y1 - y2) exp(-x/k) + y2

Answer: Option D

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