Question
16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B?
Answer: Option B
- Average = (76 x 16) - (75 x 10) 6 = 1216 - 750 6 = 466 6 = 233 3 = 77 2 3
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- Average = (76 x 16) - (75 x 10) 6 = 1216 - 750 6 = 466 6 = 233 3 = 77 2 3
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