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Question
1417×1417 can be represented as ___________.
Options:
A .  1417+17
B .  (142)17
C .  (14×14)17
D .  All of the above
Answer: Option D
:
D
For any positive real number 'a' and integers 'm' and 'n', we define
1.
am×an=am+n
2. (am)n=amn
3. (ab)m=ambm andifa=b, the expression becomes (a×a)m=(a2)m=a2m.
​​​​​​So, using first rule, we have
1417+17=1427
Now, using secondrule,
(142)17= 1427
Finally, using thirdrule,
(14×14)17=1427
Hence, we see that all the three results are same.

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