10 5 g of a sample of water contained 16.2 g of C a ( H C O 3 ) 2 . It's hardness is Options: A . &nbsp200 ppm B . &nbsp300 ppm C . &nbsp60 ppm D . &nbsp100 ppm

Answer: Option D : D 10 5 g H 2 O − 16.2 g C a ( H C O 3 ) 2 10 6 g H 2 O − ? 10 6 × 16.2 10 5 = 162 p p m o f C a ( H C O 3 ) 2 162 p p m C a ( H C O 3 ) 2 = 100 p p m C a C O 3

105 g of a sample of water contained 16.2 g of Ca(HCO3)2. It's hardness is

Question

10^{5}

g of a sample of water contained 16.2 g of

C a (H C O_{3})_{2}

. It's hardness is

Options:

A . 200 ppm

B . 300 ppm

C . 60 ppm

D . 100 ppm

Answer: Option D
:
D

10^{5} g H_{2} O - 16.2 g C a (H C O_{3})_{2}

10^{6} g H_{2} O - ?

\frac{10^{6} \times 16.2}{10^{5}} = 162 p p m o f C a (H C O_{3})_{2}

162 p p m C a (H C O_{3})_{2} = 100 p p m C a C O_{3}

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