Question
The atomic number of vanadium (V), chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26 which one of these may be expected to have the highest second ionization enthalpy
Answer: Option B
:
B
V = 1s2,2s2,2p6,3s2,3p6,3d3,4s2
Cr = 1s2,2s2,2p6,3s2,3p6,3d3,4s1
V = 1s2,2s2,2p6,3s2,3p6,3d5,4s2
Fe = 1s2,2s2,2p6,3s2,3p6,3d6,4s2
In second ionization enthalpy Cr+has exact half filledd-sub shell.
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:
B
V = 1s2,2s2,2p6,3s2,3p6,3d3,4s2
Cr = 1s2,2s2,2p6,3s2,3p6,3d3,4s1
V = 1s2,2s2,2p6,3s2,3p6,3d5,4s2
Fe = 1s2,2s2,2p6,3s2,3p6,3d6,4s2
In second ionization enthalpy Cr+has exact half filledd-sub shell.
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