Question
Find the sum of the first five terms of the series: 3, 12, 48...
Answer: Option B
:
B
Sn=[a(rn−1)r−1]
In the question a = 3, r = 4, n = 5
S5=3×(45−1)(4−1)=1023
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:
B
Sn=[a(rn−1)r−1]
In the question a = 3, r = 4, n = 5
S5=3×(45−1)(4−1)=1023
Was this answer helpful ?
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