∫ π 2 0 c o s x 1 + s i n x d x = Options: A . &nbsplog 2 B . &nbsplog e C . &nbsp12 log 3 D . &nbsp0

Answer: Option A : A put 1+ sin x =t T h e n ∫ π 2 0 c o s x 1 + s i n x d x = [ l o g | 1 + s i n x | ] π 2 0 = l o g 2

∫π20 cos x1+sin xdx=

Question

\int_{0}^{\frac{π}{2}} \frac{c o s x}{1 + s i n x} d x =

Options:

A . log 2

B . log e

C . 12 log 3

D . 0

Answer: Option A
:
A
put 1+ sin x =t

T h e n \int_{0}^{\frac{π}{2}} \frac{c o s x}{1 + s i n x} d x = {[l o g | 1 + s i n x |]}_{0}^{\frac{π}{2}} = l o g 2

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