Question
∣∣
∣∣1ab−a1c−b−c1∣∣
∣∣=
∣∣1ab−a1c−b−c1∣∣
∣∣=
Answer: Option A
:
A
∣∣
∣∣1ab−a1c−b−c1∣∣
∣∣=1(1+c2)−a(−a+bc)+b(ac+b)=1+a2+b2+c2.
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:
A
∣∣
∣∣1ab−a1c−b−c1∣∣
∣∣=1(1+c2)−a(−a+bc)+b(ac+b)=1+a2+b2+c2.
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