$$\frac{{{\text{tan}}\theta }}{{1 - {\text{cot}}\theta }}{\text{ + }}\frac{{{\text{cot}}\theta }}{{1 - {\text{tan}}\theta }}$$ is equal to? Options: A . &nbsp1 - tanθ - cotθ B . &nbsptanθ - cotθ +1 C . &nbspcotθ - tanθ + 1 D . &nbsptanθ + cotθ + 1

$$\frac{{{\text{tan}}\theta }}{{1 - {\text{cot}}\theta }}{\text{ + }}\frac{{{\te

Question

$$\frac{{{\text{tan}}\theta }}{{1 - {\text{cot}}\theta }}{\text{ + }}\frac{{{\text{cot}}\theta }}{{1 - {\text{tan}}\theta }}$$ is equal to?

Options:

A . 1 - tanθ - cotθ

B . tanθ - cotθ +1

C . cotθ - tanθ + 1

D . tanθ + cotθ + 1

Answer: Option D

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