$$\frac{{3\sqrt 2 }}{{\sqrt 6 + \sqrt 3 }} - $$ $$\frac{{2\sqrt 6 }}{{\sqrt 3

Question

$$\frac{{3\sqrt 2 }}{{\sqrt 6 + \sqrt 3 }} - $$ $$\frac{{2\sqrt 6 }}{{\sqrt 3 + 1}} + $$ $$\frac{{2\sqrt 3 }}{{\sqrt 6 + 2}}$$ is equal to = ?

Options:

A . 3

B . 2

C . 0

D . $$\sqrt 3 $$

Answer: Option C

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