$$\frac{1}{2}\left( {\log x + \log y} \right)$$ will equal to $$\log \left( {\frac{{x + y}}{2}} \right)$$ if - Options: A . &nbspy = 0 B . &nbspx = $$\sqrt {\text{y}} $$ C . &nbspx = y D . &nbspx = $$\frac{{\text{y}}}{2}$$

$$\frac{1}{2}\left( {\log x + \log y} \right)$$ will equal to $$\log \left(

Question

$$\frac{1}{2}\left( {\log x + \log y} \right)$$ will equal to $$\log \left( {\frac{{x + y}}{2}} \right)$$ if -

Options:

A . y = 0

B . x = $$\sqrt {\text{y}} $$

C . x = y

D . x = $$\frac{{\text{y}}}{2}$$

Answer: Option C

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