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Question
(a) For any triangle ABC, draw: [4 MARKS]
(i) All possible medians.
(ii) All possible altitudes.
(b) Find the unknown angles x and y.
 (a) For Any Triangle ABC, Draw: [4 MARKS](i) All Possible Me...
Answer:
:
(a) Each sub-part: 1 Mark
(b) Each angle: 1 Mark
(a)
(i)(a) For Any Triangle ABC, Draw: [4 MARKS](i) All Possible Me...(ii)(a) For Any Triangle ABC, Draw: [4 MARKS](i) All Possible Me...
(b)
(a) For Any Triangle ABC, Draw: [4 MARKS](i) All Possible Me...
BAC=92
ACB=x (Equal sides have equal angles opposite to them.)
ACB+ABC+92=180
2x+92=180
x+46=90
x=9046
x=44
ACB+y=180x+y=180
44+y=180
y=18044
y=136

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