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Quantitative Aptitude

SURDS AND INDICES MCQs

Surds & Indices, Indices And Surds, Power

Total Questions : 753 | Page 19 of 76 pages
Question 181. (17)^3.5 x (17)? = 17^8
  1.    2.29
  2.    2.75
  3.    4.25
  4.    4.5
 Discuss Question
Answer: Option D. -> 4.5
Answer: (d).4.5
Question 182. Given that 10^(0.48) = x, 10^(0.70) = y and x^z = y^2, then the value of z is close to:
  1.    1.45
  2.    1.88
  3.    2.9
  4.    3.7
 Discuss Question
Answer: Option C. -> 2.9
Answer: (c).2.9
Question 183. If 3^(x - y) = 27 and 3^(x + y) = 243, then x is equal to:
  1.    0
  2.    2
  3.    4
  4.    6
 Discuss Question
Answer: Option C. -> 4
Answer: (c).4
Question 184. If 5^a = 3125, then the value of 5^(a - 3) is:
  1.    25
  2.    125
  3.    625
  4.    1625
 Discuss Question
Answer: Option A. -> 25
Answer: (a).25
Question 185. (256)^0.16 x (256)^0.09 = ?
  1.    4
  2.    16
  3.    64
  4.    256.25
 Discuss Question
Answer: Option A. -> 4
Answer: (a).4
Question 186. The value of [(10)^150 ÷ (10)^146]
  1.    1000
  2.    10000
  3.    100000
  4.    106
 Discuss Question
Answer: Option B. -> 10000
Answer: (b).10000
Question 187. (0.04)^-1.5 = ?
  1.    25
  2.    125
  3.    250
  4.    625
 Discuss Question
Answer: Option B. -> 125
Answer: (b).125
Question 188. If m and n are whole numbers such that m^n = 121, the value of (m - 1)^(n + 1) is:
  1.    1
  2.    10
  3.    121
  4.    1000
 Discuss Question
Answer: Option D. -> 1000
Answer: (d).1000
Question 189. (25)^7.5 x (5)^2.5 ÷ (125)^1.5 = 5^?
  1.    8.5
  2.    13
  3.    16
  4.    17.5
 Discuss Question
Answer: Option B. -> 13
Answer: (b).13
Question 190.

Find the largest from among `root4(6), sqrt(2) and root3(4)`.


  1.    `root2(3)`
  2.    `root3(4)`
  3.    `root3(5)`
  4.    `root2(4)`
 Discuss Question
Answer: Option B. -> `root3(4)`

Sol.         Given surds are of order 4, 2 and 3 respectively. Their L.C.M. is 12 .

                Changing each to a surd of order 12 , we get :

                 `root4(6) = 6^( 1/4) = 6^( 1/4 xx 3/5) = (6^(3/12)) = (6^3)^(1/12) = (216)^(1/12)`

                 `sqrt(2) = 2^(1/2) = 2^(1/2 xx  6/6) = (2^(6/12)) = (2^6)^(1/12) = (64)^(1/12)`

                 `root3(4) = 4^(1/2) = 4^(1/3 xx 4/4) = (4^(4/12)) =( 4^4)^(1/12) = (256)^(1/12)`  

                    Clearly , `(256)^(1/12)  >  (216)^(1/12)     i.e. , root3(4)`



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