Quantitative Aptitude > Interest
SIMPLE INTEREST MCQs
Total Questions : 234
| Page 8 of 24 pages
Answer: Option C. -> Rs.7200
Answer: (c)If the sum lent be Rs. x, then${x × 2.5 × 3}/100 = 540$$x = {540 × 100}/{2.5 × 3}$ = Rs.7200Using Rule 13,$P_1 = P, R_1 = R, T_1$ = 3$P_2 = P, R_2 = R + 2.5%, T_2$ = 3S.I. = Rs.540540 = ${P × (R + 2.5%) × 3 - P × R × 3}/100$54000 = 7.5PP = $540000/75$P = Rs.7200
Answer: (c)If the sum lent be Rs. x, then${x × 2.5 × 3}/100 = 540$$x = {540 × 100}/{2.5 × 3}$ = Rs.7200Using Rule 13,$P_1 = P, R_1 = R, T_1$ = 3$P_2 = P, R_2 = R + 2.5%, T_2$ = 3S.I. = Rs.540540 = ${P × (R + 2.5%) × 3 - P × R × 3}/100$54000 = 7.5PP = $540000/75$P = Rs.7200
Answer: Option A. -> 8
Answer: (a)Using Rule 1Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ orS.I. = ${\text"P × R × T"/100$P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$ A = P + S.I. or S.I. = A - P
Answer: (a)Using Rule 1Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ orS.I. = ${\text"P × R × T"/100$P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$ A = P + S.I. or S.I. = A - P
Answer: Option D. -> 21
Answer: (d)Case I,Interest = PrincipalRate = ${Interest × 100}/\text"Principal × Time"$= $100/7%$ per annumCase II,Interest = 3 × PrincipalTime = ${Interest × 100}/\text"Principal × Time"$= ${3 × 100}/{100/7}$ = 3 × 7 = 21 years
Answer: (d)Case I,Interest = PrincipalRate = ${Interest × 100}/\text"Principal × Time"$= $100/7%$ per annumCase II,Interest = 3 × PrincipalTime = ${Interest × 100}/\text"Principal × Time"$= ${3 × 100}/{100/7}$ = 3 × 7 = 21 years
Answer: Option A. -> 6$2/3$%
Answer: (a)Let principal be Rs.x.Amount = Rs.2xInterest = Rs.(2x - x) = Rs.xRate = ${S.I. × 100}/\text"Principal × Time"$= ${x × 100}/{x × 15} = 20/3$= 6$2/3%$ per annum
Answer: (a)Let principal be Rs.x.Amount = Rs.2xInterest = Rs.(2x - x) = Rs.xRate = ${S.I. × 100}/\text"Principal × Time"$= ${x × 100}/{x × 15} = 20/3$= 6$2/3%$ per annum
Answer: Option D. -> 50%
Answer: (d)Principal = Rs.x (let)Amount = Rs.5xInterest = Rs.(5x - x) = Rs.4xRate = ${S.I. × 100}/\text"Principal × Time"$= ${4x × 100}/{x × 8}$ = 50% per annum
Answer: (d)Principal = Rs.x (let)Amount = Rs.5xInterest = Rs.(5x - x) = Rs.4xRate = ${S.I. × 100}/\text"Principal × Time"$= ${4x × 100}/{x × 8}$ = 50% per annum
Answer: Option C. -> 16$2/3$%
Answer: (c)The sum gets doubled in 5 years and tripled in 12 years.Clearly rate of interest for 12 years will be lower.Let Principal be x.then, Rate = ${SI × 100}/\text"Principal × Time"$= ${2x × 100}/{x × 12} = 50/3 = 16{2}/3%$Using Rule 3,$R_1 = {(2 - 1)}/5 × 100%$ = 20%$R_2 = {(3 - 1)}/12 × 100% = 16{2}/3%$Lower rate of interest =16$2/3%$
Answer: (c)The sum gets doubled in 5 years and tripled in 12 years.Clearly rate of interest for 12 years will be lower.Let Principal be x.then, Rate = ${SI × 100}/\text"Principal × Time"$= ${2x × 100}/{x × 12} = 50/3 = 16{2}/3%$Using Rule 3,$R_1 = {(2 - 1)}/5 × 100%$ = 20%$R_2 = {(3 - 1)}/12 × 100% = 16{2}/3%$Lower rate of interest =16$2/3%$
Answer: Option C. -> 10%
Answer: (c)Using Rule 1,Let the rate of interest per annum be r%According to the question,${5000 × 2 × r}/100 + {3000 × 4 × r}/100 = 2200$100r + 120r = 2200220 r = 2200r = $2200/220$ = 10%
Answer: (c)Using Rule 1,Let the rate of interest per annum be r%According to the question,${5000 × 2 × r}/100 + {3000 × 4 × r}/100 = 2200$100r + 120r = 2200220 r = 2200r = $2200/220$ = 10%
Answer: Option D. -> Rs.10,000
Answer: (d)Using Rule 1,Let the sum lent at 4% = Rs.xAmount at 5%= (16000 - x )According to the question,${x × 4 × 1}/100 + {(16000 - X) × 5 × 1}/100$ = 7004x + 80000 - 5x = 70000x = 80000 - 70000 = Rs.10000
Answer: (d)Using Rule 1,Let the sum lent at 4% = Rs.xAmount at 5%= (16000 - x )According to the question,${x × 4 × 1}/100 + {(16000 - X) × 5 × 1}/100$ = 7004x + 80000 - 5x = 70000x = 80000 - 70000 = Rs.10000
Answer: Option C. -> 13%
Answer: (c)S.I. for 1$1/2$ years= Rs.(873 - 756) = Rs.117S.I. for 2 years= Rs.$(117 × 2/3 × 2)$ = Rs.156Principal = 756 - 156 = Rs.600Now, P = 600, T = 2, S.I. = 156R = ${100 × S.I.}/{P × T}$= ${100 × 156}/{600 × 2}$ = 13%Using Rule 12,Rate of interest= $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100= $({756 - 873}/{873 × 2 - 756 × 7/2}) × 100$= $({- 117}/{1746 - 2646}) × 100$= $({- 117}/{- 900})$ × 100 = 13%
Answer: (c)S.I. for 1$1/2$ years= Rs.(873 - 756) = Rs.117S.I. for 2 years= Rs.$(117 × 2/3 × 2)$ = Rs.156Principal = 756 - 156 = Rs.600Now, P = 600, T = 2, S.I. = 156R = ${100 × S.I.}/{P × T}$= ${100 × 156}/{600 × 2}$ = 13%Using Rule 12,Rate of interest= $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100= $({756 - 873}/{873 × 2 - 756 × 7/2}) × 100$= $({- 117}/{1746 - 2646}) × 100$= $({- 117}/{- 900})$ × 100 = 13%
Answer: Option D. -> Rs.600
Answer: (d)Using Rule 1,Simple interest gained from Rs.500= ${500 × 12 × 4}/100$ = Rs.240Let the other Principal be x.S.I. gained = Rs.(480 - 240) = Rs.240${x × 10 × 4}/100$ = 240$x = {240 × 100}/40$ = Rs.600
Answer: (d)Using Rule 1,Simple interest gained from Rs.500= ${500 × 12 × 4}/100$ = Rs.240Let the other Principal be x.S.I. gained = Rs.(480 - 240) = Rs.240${x × 10 × 4}/100$ = 240$x = {240 × 100}/40$ = Rs.600