11th And 12th > Physics
RAY OPTICS CURVED MIRRORS MCQs
Total Questions : 30
| Page 2 of 3 pages
Answer: Option A. ->
(n – 1) f
:
A
By using m=ff−u
Here m=+1n,f→+f So, +1n=+f+f−u⇒u=−(n−1)f
:
A
By using m=ff−u
Here m=+1n,f→+f So, +1n=+f+f−u⇒u=−(n−1)f
Answer: Option D. ->
A real, inverted, same-sized image can be formed using a convex mirror
:
D
Convex mirror always forms, virtual, erect and smaller image.
:
D
Convex mirror always forms, virtual, erect and smaller image.
Answer: Option A. ->
10 cm
:
A
No change in focal length, because f depends only upon radius of curvature R.
:
A
No change in focal length, because f depends only upon radius of curvature R.
Answer: Option B. ->
√x1x2
:
B
Given u=(f+x1) and v=(f+x2)
The focal length f=uvu+v=(f+x1)(f+x2)(f+x1)+(f+x2)
On solving, we get f2=x1x2 or f=√x1x2
:
B
Given u=(f+x1) and v=(f+x2)
The focal length f=uvu+v=(f+x1)(f+x2)(f+x1)+(f+x2)
On solving, we get f2=x1x2 or f=√x1x2
Answer: Option C. ->
0.55 cm
:
C
By using IO=ff−u
Here O+5cm,f=−R2=−10cm,u=−1m=−100cm
So, I+5=−10−10−(−100)⇒I=−0.55cm.
:
C
By using IO=ff−u
Here O+5cm,f=−R2=−10cm,u=−1m=−100cm
So, I+5=−10−10−(−100)⇒I=−0.55cm.
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