C++ Programming

POINTERS TO MEMBERS MCQs

Total Questions : 5

Question 1.

What is the operation for .*?


  1.    It combines the first operand and the second operand
  2.    It seperates the first operand and the second operand
  3.    It reduces the data size
  4.    None of the mentioned
 Discuss Question
Answer is Option A. -> It combines the first operand and the second operand

The binary operator .* combines its first operand, which must be an object of class type, with 

its second operand, which must be a pointer-to-member type.

Question 2.

Which is the best design choice for using pointer to member function?


  1.    Interface
  2.    Class
  3.    Structure
  4.    None of the mentioned
 Discuss Question
Answer is Option A. -> Interface

None.

Question 3.


What is the output of this program?



1.
#include
2.
using namespace std;
3.
class Foo
4.
{
5.
public:
6.
Foo(int i = 0){ _i = i;}
7.
void f()
8.
{
9.
cout
  1.    Executed
  2.    Error
  3.    Runtime error
  4.    None of the mentioned
 Discuss Question
Answer is Option A. -> Executed

In this program, We passes the value to the class and printing it.
Output:
$ g++ ptm4.cpp
$ a.out
Executed

Question 4.


What is the output of this program?



1.
#include
2.
using namespace std;
3.
class bowl
4.
{
5.
public:
6.
int apples;
7.
int oranges;
8.
};
9.
int count_fruit(bowl * begin, bowl * end, int bowl :: *fruit)
10.
{
11.
int count = 0;
12.
for (bowl * iterator = begin; iterator != end; ++ iterator)
13.
count += iterator ->* fruit;
14.
return count;
15.
}
16.
int main()
17.
{
18.
bowl bowls[2] = {{ 1, 2 },{ 3, 5 }};
19.
cout
  1.    Executed
  2.    Error
  3.    Runtime error
  4.    None of the mentioned
 Discuss Question
Answer is Option A. -> Executed

Answer:a
Explanation:In this program, We are passing the value to the class and adding the values and printing it in the main.
Output:
$ g++ ptm3.cpp
$ a.out
I have 4 apples
I have 7 oranges

Question 5.


What is the output of this program?



1.
#include
2.
using namespace std;
3.
class Car
4.
{
5.
public:
6.
int speed;
7.
};
8.
int main()
9.
{
10.
int Car :: *pSpeed = &Car :: speed;
11.
Car c1;
12.
c1.speed = 1;
13.
cout
  1.    1
  2.    2
  3.    Both a & b
  4.    None of the mentioned
 Discuss Question
Answer is Option C. -> Both a & b

In this program, We are printing the value by direct access and another one by using pointer 

to member.
Output:
$ g++ ptm2.cpp
$ a.out
1
2