Answer: Option A. -> C2H5D
:
A
R group of the Grignard reagentcombines with hydrogen of water

Answer: Option D. -> Slaked Lime
:
D
In general, water that contains bicarbonates, sulphates and chlorides of Calcium and/or Magnesium is called hard water. If only the bicarbonates are present, then this type of hardness is called 'temporary hardness'. This can be removed either by boiling or by treating the water with measured quantity of Slaked lime. In either case, insoluble metal carbonates are formed, which are then separated out through filtration.

Answer: Option D. -> 55.5 M
:
D
The density of water is $1gc{m}^{-1}$at $4^{\circ }C$
So, molarity= $\frac{1000}{18}$=55.5M.

Answer: Option D. -> Atomic hydrogen > nascent hydrogen > molecular hydrogen
:
D
Atomic hydrogen is moreunstable and highly reactive than molecular hydrogen

Answer: Option D. -> Bond length
:
D
The two isotopes have same atomic number therefore inter nuclear distance is same.

Answer: Option C. -> Both 1 & 2
:
C
Symmetric molecules have zero dipole moment

Answer: Option B. -> Electrolysis of warm, aqueous solution of Ba(OH)2 between nickel electrodes
:
B
Electrolysis of water is the method by which the most pure form of hydrogen can be obtained since the hydrogen gas is collected in an isolated volume.

Answer: Option B. -> Cl2 +H2O2 → 2HCl + O2
:
B
$\underset{0}{C{l}_2}$ + $H_2{O}_2$ $\to$$\underset{-1}{2HCl}$ + $O_2$
In this reaction $H_2{O}_2$ works as reducing agent

Answer: Option D. -> None of these
:
D
Water containing$C{a}^{+2}$ , $M{g}^{+2}$ and $H^{+}$(>${10}^{-7}$m) is a hard water.
$H^{+}$(aq)) + $C{H}_{3}COONa$(aq) $\leftrightharpoons$$C{H}_{3}COOH$(s) + ${Na}^{+}$(aq)

Answer: Option D. -> 100 ppm
:
D
${10}^{5}g{H}_{2}O-16.2gCa(HC{O}_3{)}_2$
${10}^{6}g{H}_{2}O-?$
$\frac{{10}^6\times 16.2}{{10}^5}=162ppmofCa(HC{O}_3{)}_2$
$162ppmCa(HC{O}_3{)}_2=100ppmCaC{O}_3$