Question 81.Convert the following fractions into decimals and find the sum of these decimals that rounded up to 2 decimal places. 12, 52, 49, 520, 310, 7100, 1002, 10000010000000, 1248, 999, 525 Ans: ___
: 12=0.5 52=2.5 49=0.4444 520=0.25 310=0.3 7100=0.07 1002=50 10000010000000=0.01 1248=0.25 999=0.09090909 525=0.20 ∴ Sum = 54.615 When rounded up to two decimal place, Then Sum = 54.62
Question 82.Convert the following fractions into decimals and find the sum of these decimals that rounded up to 2 decimal places. 12, 52, 49, 520, 310, 7100, 1002, 10000010000000, 1248, 999, 525 Ans: ___
: 12=0.5 52=2.5 49=0.4444 520=0.25 310=0.3 7100=0.07 1002=50 10000010000000=0.01 1248=0.25 999=0.09090909 525=0.20 ∴ Sum = 54.615 When rounded up to two decimal place, Then Sum = 54.62
Question 83. A bag contains 25 kg of rice at ₹ 20.04 per kg and 20 kg of dal at ₹ 15.28 per kg. What is the total cost of 5 such bags?
Answer: Option A. -> ₹ 4033 : A Cost of rice in one bag = 25×20.04 =₹501 Cost of dal in one bag = 20×15.28 =₹305.6 Total cost of one bag = 501 + 305.6 =₹806.6 Cost of 5 such bags = 5×806.6 =₹4033
Question 84. On multiplying a decimal number by 100, we shift the decimal point (i) ______ places to the (ii) ______ and on dividing a decimal number by 100, we shift the decimal point, (iii)_______ places to the (iv) _______.
Answer: Option D. -> i) two ii) right iii) two iv) left : D Let's take an example and visualize. 2.48×100=248.0 [Decimal point shifted two places to the right] 2480÷100=2480100=24.80[Decimal point shifted two places to the left]
Answer: Option B. -> 800 g : B Total weightof fruits = 4 kg Total number of children among whom the fruits are to be shared equally= 5 Thus, the total quantityof fruits each child would get = 45kg = 45×1000grams =40005g = 800 g
Answer: Option B. -> 8.9345 : B Shifting the decimal point 3 places to the right of the decimal number 0.89345, we have 0.89345×1000=893.45 ∴(0.89345×1000)+8.9345−893.45 =893.45+8.9345−893.45 =0+8.9345 =8.9345
Question 88. A bag contains 25 kg of rice at ₹ 20.04 per kg and 20 kg of dal at ₹ 15.28 per kg. What is the total cost of 5 such bags?
Answer: Option A. -> ₹ 4033 : A Cost of rice in one bag = 25×20.04 =₹501 Cost of dal in one bag = 20×15.28 =₹305.6 Total cost of one bag = 501 + 305.6 =₹806.6 Cost of 5 such bags = 5×806.6 =₹4033
Answer: Option B. -> 8.9345 : B Shifting the decimal point 3 places to the right of the decimal number 0.89345, we have 0.89345×1000=893.45 ∴(0.89345×1000)+8.9345−893.45 =893.45+8.9345−893.45 =0+8.9345 =8.9345
