Fractions And Decimals(7th Grade > Mathematics ) Questions and answers for exam Preparation

7th Grade > Mathematics

FRACTIONS AND DECIMALS MCQs

Fractions, Decimals

Total Questions : 227 | Page 8 of 23 pages

Question 71. Find the least fraction, which must be multiplied to

(1 \frac{2}{4} - \frac{1}{2} + 3 \frac{6}{16} - \frac{1}{16} + \frac{2}{8}

) to make it an integer.

Discuss Question

Answer: Option B. -> 161
:
B

(1 \frac{2}{4}

\frac{1}{2}

\frac{6}{16}

\frac{1}{16}

\frac{2}{8}

)
=

\frac{6}{4} - \frac{1}{2} + \frac{54}{16} - \frac{1}{16} + \frac{2}{8}

Taking LCM of denominators and solving,

\frac{24 - 8 + 54 - 1 + 4}{16}

\frac{73}{16}

Now, If we multiply

\frac{73}{16}

\frac{16}{1}

, it becomes 73, which is an integer
Hence,

\frac{16}{1}

is the required fraction.

Question 72.

[5 \frac{1}{4} - \frac{2}{5} \times 5 \frac{5}{9} + (\frac{1}{2} + \frac{3}{4})]

is equal to:

916
7718
2412
1224

Discuss Question

Answer: Option B. -> 7718
:
B
Given

[5 \frac{1}{4} - \frac{2}{5} \times 5 \frac{5}{9} + (\frac{1}{2} + \frac{3}{4})]

ApplyBODMAS rule to solve
=

[\frac{21}{4} - (\frac{2}{5} \times \frac{50}{9}) + \frac{5}{4}]

[\frac{21}{4} - (\frac{20}{9}) + \frac{5}{4}]

Taking LCM of denominators, we have

\frac{189 - 80 + 45}{36} = \frac{154}{36} = \frac{77}{18}

[5 \frac{1}{4} - \frac{2}{5} \times 5 \frac{5}{9} + (\frac{1}{2} + \frac{3}{4})] = \frac{77}{18}

Question 73.

[5 \frac{1}{4} - \frac{2}{5} \times 5 \frac{5}{9} + (\frac{1}{2} + \frac{3}{4})]

is equal to:

916
7718
2412
1224

Discuss Question

Answer: Option B. -> 7718
:
B
Given

[5 \frac{1}{4} - \frac{2}{5} \times 5 \frac{5}{9} + (\frac{1}{2} + \frac{3}{4})]

ApplyBODMAS rule to solve
=

[\frac{21}{4} - (\frac{2}{5} \times \frac{50}{9}) + \frac{5}{4}]

[\frac{21}{4} - (\frac{20}{9}) + \frac{5}{4}]

Taking LCM of denominators, we have

\frac{189 - 80 + 45}{36} = \frac{154}{36} = \frac{77}{18}

[5 \frac{1}{4} - \frac{2}{5} \times 5 \frac{5}{9} + (\frac{1}{2} + \frac{3}{4})] = \frac{77}{18}

Question 74. Simplify the following expression and choose the correct answer:

\frac{0 \times (\frac{5}{9} \times \frac{2}{3}) + \frac{5}{6} \times 9 \times 0}{(\frac{4}{5} + \frac{3}{5} + \frac{1}{2})}

Discuss Question

Answer: Option D. -> 0
:
D
Concentrate on numerator. The expression has '

0

' multiplied to it, and any numbermultiplied by'

0

' is '

0

'.
And 0 divided by any numberalways '

0

'.
Hence the answer is '

0

Question 75. A person bought

3 \frac{1}{2} k g

of apples,

2 \frac{2}{3} k g

of grapes and

1 \frac{1}{3} k g

of oranges. He wants to divide them among

4

people. Find the amount of fruits(in kg) that each person will receive.

138 kg
158 kg
178 kg
278 kg

Discuss Question

Answer: Option C. -> 178 kg
:
C
First, let usdo the conversion of mixed fractions into improper fractions.
i.e

3 \frac{1}{2} = \frac{(2 \times 3) + 1}{2} = \frac{7}{2}

2 \frac{2}{3} = \frac{(3 \times 2) + 2}{3} = \frac{8}{3}

, and

1 \frac{1}{3} = \frac{(3 \times 1) + 1}{3} = \frac{4}{3}

Total quantityof fruits = (\frac{7}{2} + \frac{8}{3} + \frac{4}{3}) k g

= \frac{7}{2} + 4

= \frac{7}{2} + \frac{8}{2}

= \frac{15}{2}

kg
When

\frac{15}{2} k g

is divided among 4people,
each person's share

= \frac{\frac{15}{2}}{4} k g

= (\frac{15}{2} \times \frac{1}{4}) k g

= \frac{15}{8} k g

= 1 \frac{7}{8} k g

Hence, each person gets

(1 \frac{7}{8}) k g

of fruits.

Question 76. Find the least fraction, which must be multiplied to

(1 \frac{2}{4} - \frac{1}{2} + 3 \frac{6}{16} - \frac{1}{16} + \frac{2}{8}

) to make it an integer.

Discuss Question

Answer: Option B. -> 161
:
B

(1 \frac{2}{4}

\frac{1}{2}

\frac{6}{16}

\frac{1}{16}

\frac{2}{8}

)
=

\frac{6}{4} - \frac{1}{2} + \frac{54}{16} - \frac{1}{16} + \frac{2}{8}

Taking LCM of denominators and solving,

\frac{24 - 8 + 54 - 1 + 4}{16}

\frac{73}{16}

Now, If we multiply

\frac{73}{16}

\frac{16}{1}

, it becomes 73, which is an integer
Hence,

\frac{16}{1}

is the required fraction.

Question 77. Varun travelled

\frac{1}{8}

th of the journey which is equal to

56 k m

on a scooter . What is the remaining distance he has to cover?

342 km
392 km
352 km
442 km

Discuss Question

Answer: Option B. -> 392 km
:
B
Let the total distance to be covered

= d k m

Then,

\frac{1}{8} \times d

56 k m

d = (56 \times 8)km = 448km

Remaining distance= (448 - 56)km = 392km

Question 78. Varun travelled

\frac{1}{8}

th of the journey which is equal to

56 k m

on a scooter . What is the remaining distance he has to cover?

342 km
392 km
352 km
442 km

Discuss Question

Answer: Option B. -> 392 km
:
B
Let the total distance to be covered

= d k m

Then,

\frac{1}{8} \times d

56 k m

d = (56 \times 8)km = 448km

Remaining distance= (448 - 56)km = 392km

Question 79.

\frac{2 \frac{1}{2} + 2 \frac{1}{3} + 2 \frac{1}{4}}{\frac{1}{10} \times \frac{2}{5} \times \frac{125}{6}} is equals to:

Discuss Question

Answer: Option D. -> 8.5
:
D

\frac{\frac{5}{2} + \frac{7}{3} + \frac{9}{4}}{\frac{1}{10} \times \frac{2}{5} \times \frac{125}{6}}

= \frac{\frac{85}{12}}{\frac{5}{6}}

= \frac{85}{12} \times \frac{6}{5}

= \frac{17}{2} = 8.5

Question 80. The product of two fractions is

20

. If one of the fractions is

\frac{1}{4}

, then the other fraction is ___.

Discuss Question

:
Let the other fraction be

x

Then,

x \times \frac{1}{4} = 20

x = 20 \times 4 = 80

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7th Grade > Mathematics

FRACTIONS AND DECIMALS MCQs

Fractions, Decimals

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