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7th Grade > Mathematics

FRACTIONS AND DECIMALS MCQs

Fractions, Decimals


Total Questions : 227 | Page 7 of 23 pages
Question 61. 57=?49
  1.    25
  2.    5
  3.    7
  4.    35
 Discuss Question
Answer: Option D. -> 35
:
D
Equivalent fractions are fractions which have the same value and are obtained by dividing or multiplying both the numerator and the denominator of a fraction by the same number.
Now, 49÷7=7
Therefore, 57=5×77×7=3549
Hence, the missing number is 35.
Question 62. 18 as a decimal = ______
  1.    125
  2.    12.5
  3.    1.25
  4.    0.125
 Discuss Question
Answer: Option D. -> 0.125
:
D
8's friend is 125 as8×125=1000
18×125125=1251000=0.125
Question 63. 3×46+4×5125×710 =
  1.    56
  2.    13
  3.    16
  4.    35
 Discuss Question
Answer: Option C. -> 16
:
C
3×46+4×5125×7103×46+4×5125×71042+5372LCM of 2×3=64×32×3+5×23×27×32×312+102122216=16
Question 64. If one pencil costs ₹ 5.75, then the cost of 100 such pencils is _____.
  1.    ₹ 0.575 
  2.    ₹ 57.50 
  3.    ₹ 575
  4.    ₹ 5750
 Discuss Question
Answer: Option C. -> ₹ 575
:
C
Given: Cost of 1 pencil = ₹ 5.75
Cost of 100 pencils =(5.75×100)
Cost of 100 pencils = ₹575
Question 65. Find the value.
500+4+4100=___
  1.    54.4
  2.    54.04
  3.    504.4
  4.    504.04
 Discuss Question
Answer: Option D. -> 504.04
:
D
We have to do the addition:
=500+4+4100
=500+4+0.04
500.004.00+0.04––––––––504.04––––––––
Question 66. Six cases of paper cost ₹ 156.49. How much does one cost?
  1.    ₹ .26.19
  2.    ₹ 25.45
  3.    ₹ 26.08
  4.    ₹ 25.18
 Discuss Question
Answer: Option C. -> ₹ 26.08
:
C
cost of six cases = ₹156.49
Cost of one case=156.496
156.496=26.08166...
Approximately equal to ₹26.08 (Rounding off).
Question 67. A shopkeeper wants to distribute 20.7 kgs of sugar into 9 equal jars. How much sugar would go into each jar?  
  1.    2.7 kg
  2.    2.1 kg
  3.    2.3 kg
  4.    3.1 kg
 Discuss Question
Answer: Option C. -> 2.3 kg
:
C
To find the amount of sugar that goes into each jar, we need to divide 20.7 kg by 9.
A Shopkeeper Wants To Distribute 20.7 Kgs Of Sugar Into 9 Eq...
20.79kg=2.3kg
Each jar will have 2.3 kg of sugar.
Question 68. 1.10.03=    ____
  1.    1.7
  2.    1.77
  3.    1.07
  4.    1.70
 Discuss Question
Answer: Option C. -> 1.07
:
C
Since 0.03 has two decimal places, we use the equivalent decimal of 1.1 with two decimal places.
i.e., 1.10.03=1.100.0.3
1./10/0100.03–––––––––1.07––––––––
Question 69. Solve 13(56×918)+29.
  1.    436
  2.    536
  3.    636
  4.    736
 Discuss Question
Answer: Option B. -> 536
:
B
13(56×918)+29
=13(1536)+29
=131536+29
Taking L.C.M of denominators, 1215+836=536
Question 70. 212+213+214110×25×1256 is equals to:
  1.    5.5
  2.    6.5
  3.    7.5
  4.    8.5
 Discuss Question
Answer: Option D. -> 8.5
:
D
52+73+94110×25×1256
=851256
=8512×65
=172=8.5

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