Answer: Option A. ->
:

In kilograms: 1 Mark
In grams: 1 Mark
1 Kilogram = 1000 grams
Or 1 gram=$\frac{1}{1000}$ kilograms
Let x kilograms = 3460 g
$=\left(\frac{3460}{1000}\right)$ kilograms
= 3.460 kilograms
3460 grams = 3.460 kilograms
Now $17\frac{1}{2}\text{kg}=\frac{17\times 2+1}{2}$
=$\frac{34+1}{2}$
=$\frac{35}{2}\text{kg}$
=$\frac{35}{2}\times 1000\text{gms}$
=$(35\times 500)\text{gm}$
=$17500\text{gms}$

Answer: Option A. ->
:
Each answer: 1 Mark
Given that:
Fraction of the apple Kartik ate $=\frac{3}{5}$
Fraction of the apple uneaten $=1-\frac{3}{5}$
$=\frac{5-3}{5}$
$=\frac{2}{5}$
This part was eaten by his brother Bharath
$\therefore$ Bharath ate $\frac{2}{5}$th part of the apple.
Comparing two fractions we have
$\frac{3}{5}\&\frac{2}{5}$
Clearly $\frac{3}{5}>\frac{2}{5}$
$\Rightarrow$ Karthik had the larger share which was larger by $\frac{3}{5}-\frac{2}{5}=\frac{1}{5}$.

Answer: Option A. ->
:

Conversion Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
We know that
1 km=1000 m
Converting kilometers into meters
we have 
18 km = 18$\times$1000=18000 metres

Difference = 29000-18000

                     =11000 metres

                    Or

 29000 metres= 29 km

 Difference     = 29-18

                         =11 km

Answer: Option A. ->
:

Conversion Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
In an equilateral triangle, all the sides are equal.

Let the side of an equilateral triangle be=  a cm   where a= 3.4 m  ( given)

 Now  Perimeter =  a+ a+a=(3a) m

 = (3)*(3.4)

  =10.2m 
Hence perimeter of the equilateral triangle = 10.2m. 
Now, 1 m= 100cm
$\therefore$ 10.2m=10.2$\times$100 = 1020 cm.
Hence, the perimeter of the triangle is 1020 cm.

Answer: Option A. ->
:
Steps: 2 Mark
Answer: 1 Mark
Given that
Mohan finishes the work in $\frac{7}{12}$ of an hour.
Also given that
Keerthi finishes the work in $\frac{3}{4}$ of an hour.
Now, $\frac{7}{12}$ of an hour
$\Rightarrow \frac{7}{12}\times 60minutes$
$\Rightarrow 35mins$
Again
$\frac{3}{4}$ of an hour
$\Rightarrow \frac{3}{4}\times 60$
$\Rightarrow 45minutes$
Clearly, Keerthi worked more by 45 - 35 = 10 more minutes.
Now, when expressed as a fraction
$\frac{10}{60}=\frac{1}{6}$ of an hour.
Alternative Way
Method II
Now, $\frac{7}{12}and\frac{3}{4}$
Making them Like fractions we have
$\frac{7\times 1}{12\times 1}\&\frac{3\times 3}{4\times 3}$
i.e. $\frac{7}{12}<\frac{9}{12}$
Clearly, Keerthi who takes ${\frac{3}{4}}^{th}$ of an hour takes longer than Mohan who takes ${\frac{7}{12}}^{th}$ of an hour.
So, subtracting we have
$\frac{9}{12}-\frac{7}{12}=\frac{2}{12}=\frac{1}{6}$ of an hour.

Answer: Option A. ->
:

Steps: 2 Marks
Application: 1 Mark
Result: 1 Mark
Given that
Area of the shaded portion = $\frac{10}{4}$ $m^2$

The circle is divided into 8 equal parts

Area of the circle = (8)$\times$$\frac{10}{4}$

                           = 20 $m^2$
Area of unshaded part = Total area - shaded area
                                      = 20 - $\frac{10}{4}$ $m^2$
                                      = $\frac{80-10}{4}{m}^2$
                                      = $\frac{70}{4}$ = 17.5 $m^2$
Hence, area of the unshaded portion is 17.5 $m^2$

Answer: Option A. ->
:

Steps: 1 Mark
Application: 1 Mark
Answer: 1 Mark
Given that
Team 'A' scored 260 runs in 50 overs. 
So, run rate of the team batting first =(260/50)

= 5.2 runs per over
The team batting second scored at half the run rate of the team batting first

Run rate of team the  batting second
= (5.2/2)

= 2.6 runs per over

Runs scored by the  team batting second
$=\left(50\right)\times \left(2.6\right)$

= 130 
Hence, the team batting second scored 130 runs.

Answer: Option A. ->
:

Bodmas operation: 1 Mark
Simplifying the numerator and the denominator: 1 Mark
Answer: 2 Marks
Multiply and divide the equation by 100 
=$\frac{(8\times 7)-(6.5\times 6)}{(6.5\times 6)-(6.2\times 6)}$
=$\frac{(56-39)}{(39-37.2)}$
=$\frac{17}{1.8}$
=$\frac{170}{18}$
=$\frac{85}{9}$

Answer: Option A. ->
:
Making them into like decimals: 1 Mark
Mathematical operation: 1 Mark
Fraction expression: 2 Marks
Now converting the decimals given into like decimals and adding it.
$\underset{–}{0}7.205\underset{–}{0}$
$\underset{–}{0}8.012\underset{–}{0}$
$\underset{–}{0}3.1\underset{–}{0}\underset{–}{0}\underset{–}{0}$
$\underset{–}{0}4.9\underset{–}{0}\underset{–}{0}\underset{–}{0}$
$27.3\underset{–}{0}\underset{–}{0}\underset{–}{0}$
$\underset{–}{0}3.0009$
$\underset{–}{0}8.0102$
We get   $61.4281$
(II) Now,  61. 4281 can be rounded up
to 61.428
to 61. 43
to 61. 4
Now
$61.4=\frac{61.4÷2}{100÷2}=\frac{307}{50}=6\frac{7}{50}$
 

Answer: Option A. ->
:
Steps: 2 Mark
Application: 1 Mark
Answer: 1 Mark
Given that
Anubha's father weighs 91 kg.
Anubha's dog's weight=$\frac{1}{7}$ of Anubha's father's weight
$\Rightarrow \frac{1}{7}\times 91$
$\Rightarrow \frac{91}{7}\Rightarrow 13kg$

Also given
Anubha's mother's weight= 5 times Anubha's dog's weight
$=5\times 13=65kg$
$\therefore$ Anubha's mother weighs 65 kg.