Question
\(\frac{\left(243\right)^{\frac{n}{5}}\times3^{2n+1}}{9^{n}\times3^{n-1}}= ?\)
Answer: Option C
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Given Expression = \(\frac{\left(243\right)^{\frac{n}{5}}\times3^{2n+1}}{9^{n}\times3^{n-1}}\)
= \(\frac{\left(3^{5}\right)^{\left(\frac{n}{5}\right)} \times3^{2n+1}}{\left(3^{2}\right)^{n}\times3^{n-1}}\)
= \(\frac{\left(3^{5\times(\frac{n}{5})}\times3^{2n-1}\right)}{\left(3^{2n}\times3^{n-1}\right)}\)
= \(\frac{3^{n}\times3^{2n-+1}}{3^{2n}\times3^{n-1}}\)
= \(\frac{3^{(n+2n+1)}}{3^{(2n+n-1)}}\)
= \(\frac{3^{3n+1}}{3^{3n-1}}\)
= 3(3n + 1 - 3n + 1)
= 32 = 9.
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