Question
The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
Answer: Option B
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Let original length = x and original breadth = y.
Original area = xy.
New length = \( \frac{x}{2}\)
New breadth = 3y.
New area = \(\left(\frac{1}{2}x\times3y\right)= \frac{3}{2}xy\)
So, Increase % = \(\left(\frac{1}{2}xy\times\frac{1}{xy}\times100\right)\) % = 50%.
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