Question
What is the remainder when (37)2012 is divided by 25?
Answer: Option A
:
A
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A
Last two digits of (37)2012=(69)1006=(61)503=8125∣r=6.
Note - The ten's digit of 61n has a cyclicity of 5 (61-21-81-41-01-61) and 503=5k+3.
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