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Question


What is the remainder when (37)2012 is divided by 25?


Options:
A .   6
B .   21
C .   11
D .   1
E .   23
Answer: Option A
:
A

Last two digits of (37)2012=(69)1006=(61)503=8125r=6.
Note - The ten's digit of 61n has a cyclicity of 5 (61-21-81-41-01-61) and 503=5k+3.



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