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What is the minimum value of p and q in the equation x3px2+qx8=0 where p and q are positive real numbers and roots of the equation are real?


Options:
A .   4,8
B .   6,12
C .   8,12
D .   Cannot be determined
E .   8
Answer: Option B
:
B

A cubic equation can be expressed in terms of its roots as


x3-(sum of the roots) x2+(sum of the product of the roots taken 2 at a time) x-(product of the roots)=0


thus,


p= sum of roots taken one at a time


q= sum of roots taken two at a time


Product of roots =8 (given in question)


 'if the product of 2 or more numbers is constant, the sum will be minimum when they are equal'


i.e.If abc=constant, the minimum value of a+b+c will be obtained at a=b=c


 


Thus, For the sum of roots (p) to be minimum, 8 should be the product of 3 numbers that are equal to each other (difference between them should be equal). This number is 2. The roots are thus 2,2,2


P= 2+2+2= 6


And q= 2(2)+2(2)+2(2)= 12


Answer= option b


 


 



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