Question
#include<stdio.h>
int main()
{
int x=12, y=7, z;
z = x!=4 || y == 2;
printf("z=%d\n", z);
return 0;
}
What will be the output of the program?
#include<stdio.h>
int main()
{
int x=12, y=7, z;
z = x!=4 || y == 2;
printf("z=%d\n", z);
return 0;
}
Answer: Option B
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Step 1: int x=12, y=7, z; here variable x, y and z are declared as an integer and variable x and y are initialized to 12, 7 respectively.
Step 2: z = x!=4 || y == 2;
becomes z = 12!=4 || 7 == 2;
then z = (condition true) || (condition false); Hence it returns 1. So the value of z=1.
Step 3: printf("z=%dn", z); Hence the output of the program is "z=1".
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