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Question
Walking at $3/4$ of his usual speed, a man is 1$1/2$ hours late. His usual time to cover the same distance, (in hours) is
Options:
A .  5
B .  5$1/2$
C .  4
D .  4$1/2$
Answer: Option D
Answer: (d)Time and speed are inversely proportional.$4/3$ of usual time –usual time = $3/2$$1/3$ usual time = $3/2$Usual time = ${3 × 3}/2$$9/2 = 4{1}/2$ hoursUsing Rule 8,Here, A = 3, B = 4, t= $3/2$Usual time = $\text"A"/\text"Diff of A and B"$ × time= $3/{(4 - 3)} × 3/2 = 4{1}/2$ hrs.

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