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Question

Two unbiased coins are tossed. What is the probability of getting at most one head ?


Options:
A .  `1/2`
B .  `1/3`
C .  `2/3`
D .  `3/4`
Answer: Option D

Here  S =  ( HH. HT. TH . TT)

Let  E = event  of getting at most one head .

`:.`     E = (TT, HT, TH).

`:.`      P(E)  = `(n(E))/(n(S)) = 3/4`



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