Question
Two unbiased coins are tossed. What is probability of getting at most one tail ?
Answer: Option D
Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = $$\frac{{3}}{{4}}$$
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Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = $$\frac{{3}}{{4}}$$
Was this answer helpful ?
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