Question
Two persons A and B take turns in throwing a pair of dice. The first person to through 9 from both dice will be awarded the prize. If A throws first then the probability that B wins the game is
Answer: Option B
:
B
The probability of throwing 9 with two dice = 436=19
∴The probability of not throwing 9 with two dice = 89
If A is to win he should throw 9 in 1st or 3rd or 5th attempt
If B is to win, he should throw, 9 in 2nd, 4th attempt
B’s chances = (89).19+(89)3.19+.....=89×191−(89)2=817
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:
B
The probability of throwing 9 with two dice = 436=19
∴The probability of not throwing 9 with two dice = 89
If A is to win he should throw 9 in 1st or 3rd or 5th attempt
If B is to win, he should throw, 9 in 2nd, 4th attempt
B’s chances = (89).19+(89)3.19+.....=89×191−(89)2=817
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