Question
Two events A and B have the probabilities 0.25 and 0.5 respectively. The probability that both A and B simultaneously is 0.12. then the probability that neither A and nor B occurs is
Answer: Option D
:
D
P(A⋃B)=P(A)+P(B)−P(A⋂B)=0.25+0.5−0.12=0.63
Therefore required probability = 1 - P(A intersection B) = 0.37
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:
D
P(A⋃B)=P(A)+P(B)−P(A⋂B)=0.25+0.5−0.12=0.63
Therefore required probability = 1 - P(A intersection B) = 0.37
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