Question
Two dice are tossed. The probability that the total score is a prime number is:
Answer: Option B
Clearly, n(S) = (6 x 6) = 36
Let E = Event that the sum is a prime number.Then
E = {(1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5)}
$$\eqalign{
& \therefore n\left( E \right) = 15 \cr
& \therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} \cr
& = \frac{{15}}{{36}} \cr
& = \frac{5}{{12}} \cr} $$
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Clearly, n(S) = (6 x 6) = 36
Let E = Event that the sum is a prime number.Then
E = {(1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5)}
$$\eqalign{
& \therefore n\left( E \right) = 15 \cr
& \therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} \cr
& = \frac{{15}}{{36}} \cr
& = \frac{5}{{12}} \cr} $$
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