Question
Two dice are tossed . The probability that the total score is a prime number is :
Answer: Option B
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Clearly , n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number .
Then , E =[ (1, 1), (1, 2), (1, 4), (1, 6), (2, 1) , (2, 3), (2, 5), (3, 2), (3, 4) , (4, 1), (4, 3), (5, 2) , (5, 6), (6, 1), (6, 5)]
= n(E) = 15
`:.` P(E) = `(n(E))/(n(S)) = 15/36 = 5/12`
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