Question
Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6.
Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6.
Answer: Option C
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Clearly n(S) = 6*6 = 36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.
E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}
n(E)=14.
Hence p(e)=n(e)/n(s)=14/36=7/18
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