Question
Two dice are thrown together . What is the probability hat the sum of the number on the two faces is divisible by 4 or 6 ?
Answer: Option D
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Clearly , n(S) = 6 x 6 = 36.
Let E be the event that the sum of the numbers on the two faces is divisible by 4 or 6. Then
E = [(1, 3), (1, 5), (2, 2), (2, 4), (2, 6), (3, 1), (3, 3), (3, 5), (4, 2), (4, 4), ( 5, 1), (5, 3), (6, 2), (6, 6)]
`:.` n (E) = 14.
Hence , P(E) = ` (n(E))/(n(S)) = 14/36 = 7/18`
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