Question
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even ?
Answer: Option B
In a simultaneous throw of two dice, we have n (S) = (6 × 6) = 36
Let E = event of getting two numbers whose product is even.
Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
∴ n (E) = 27
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{{27}}{{36}} = \frac{3}{4}$$
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In a simultaneous throw of two dice, we have n (S) = (6 × 6) = 36
Let E = event of getting two numbers whose product is even.
Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
∴ n (E) = 27
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{{27}}{{36}} = \frac{3}{4}$$
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